190.【华为OD机试】员工派遣（二分查找—Java&Python&C++&JS实现）

题目描述：给定一个有序整数数组，编写一个函数查找特定的目标值，如果目标值存在返回其索引，否则返回 -1。

解决方案：

1. Java 实现：

public class Solution {
    public int search(int[] nums, int target) {
        int left = 0;
        int right = nums.length - 1;
        while (left <= right) {
            int mid = left + (right - left) / 2;
            if (nums[mid] == target) {
                return mid;
            } else if (nums[mid] < target) {
                left = mid + 1;
            } else {
                right = mid - 1;
            }
        }
        return -1;
    }
}

2. Python 实现：

class Solution:
    def search(self, nums: List[int], target: int) -> int:
        left, right = 0, len(nums) - 1
        while left <= right:
            mid = left + (right - left) // 2
            if nums[mid] == target:
                return mid
            elif nums[mid] < target:
                left = mid + 1
            else:
                right = mid - 1
        return -1

3. C++ 实现：

class Solution {
public:
    int search(vector<int>& nums, int target) {
        int left = 0;
        int right = nums.size() - 1;
        while (left <= right) {
            int mid = left + (right - left) / 2;
            if (nums[mid] == target) {
                return mid;
            } else if (nums[mid] < target) {
                left = mid + 1;
            } else {
                right = mid - 1;
            }
        }
        return -1;
    }
};

4. JavaScript 实现：

function search(nums, target) {
    let left = 0;
    let right = nums.length - 1;
    while (left <= right) {
        let mid = Math.floor((left + right) / 2);
        if (nums[mid] === target) {
            return mid;
        } else if (nums[mid] < target) {
            left = mid + 1;
        } else {
            right = mid - 1;
        }
    }
    return -1;
}

以上代码实现了使用二分查找算法在有序数组中查找特定目标值的功能。如果找到目标值，则返回其索引，否则返回 -1。