华为OD机试 - 数据单元的变化替换（Java & JS & Python & C & C++）

以下是不同编程语言的解决方案：

Java:

import java.util.Scanner;
 
public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        String input = sc.nextLine();
        String[] parts = input.split(",");
        for (int i = 0; i < parts.length; i++) {
            if (parts[i].equals("-1")) {
                parts[i] = String.valueOf(i);
            }
        }
        StringBuilder result = new StringBuilder();
        for (int i = 0; i < parts.length; i++) {
            result.append(parts[i]);
            if (i < parts.length - 1) {
                result.append(",");
            }
        }
        System.out.println(result.toString());
        sc.close();
    }
}

JavaScript:

process.stdin.setEncoding('utf8');
process.stdin.on('data', function (chunk) {
    var parts = chunk.trim().split(',');
    for (var i = 0; i < parts.length; i++) {
        if (parts[i] === '-1') {
            parts[i] = i.toString();
        }
    }
    console.log(parts.join(','));
});

Python:

input_str = input()
elements = input_str.split(',')
for i, elem in enumerate(elements):
    if elem == '-1':
        elements[i] = str(i)
print(','.join(elements))

C:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
 
void replace_minus_one(char *input, int length) {
    char *token;
    int i = 0;
    token = strtok(input, ",");
    while (token != NULL) {
        if (strcmp(token, "-1") == 0) {
            sprintf(token, "%d", i);
        }
        token = strtok(NULL, ",");
        i++;
    }
}
 
int main() {
    char input[1000];
    gets(input); // 注意：请不要在实际代码中使用 `gets`, 因为它不安全
    replace_minus_one(input, strlen(input));
    printf("%s\n", input);
    return 0;
}

C++:

#include <iostream>
#include <sstream>
#include <string>
 
int main() {
    std::string line;
    std::getline(std::cin, line);
    std::istringstream iss(line);
    std::string token;
    int i = 0;
    whi