创建一个能够获取摄像头并拍照上传到PHP服务器的HTML页面

以下是一个简单的HTML页面，使用JavaScript和Web API来访问用户的摄像头，并将拍摄的照片上传到一个PHP服务器。

HTML 页面 (index.html):




<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Camera Photo Upload</title>
</head>
<body>
 
<video id="video" width="640" height="480" autoplay></video>
<button id="snap">Snap Photo</button>
<canvas id="canvas" width="640" height="480"></canvas>
 
<script>
    const video = document.getElementById('video');
    const canvas = document.getElementById('canvas');
    const context = canvas.getContext('2d');
    const snap = document.getElementById('snap');
 
    // 启动摄像头
    if (navigator.mediaDevices.getUserMedia) {
        navigator.mediaDevices.getUserMedia({ video: true })
            .then(function (stream) {
                video.srcObject = stream;
            })
            .catch(function (err) {
                console.error("Error accessing the camera: " + err);
            });
    } else {
        alert("Your browser does not support the navigator.mediaDevices.getUserMedia API");
    }
 
    // 拍照
    snap.addEventListener('click', function () {
        context.drawImage(video, 0, 0, 640, 480); // 绘制到canvas
 
        // 将canvas转换为base64图片
        const base64Image = canvas.toDataURL("image/png");
 
        // 发送到PHP服务器
        const xhr = new XMLHttpRequest();
        xhr.open('POST', 'upload.php', true);
        xhr.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded');
        xhr.onload = function () {
            if (this.status == 200) {
                console.log('Photo uploaded successfully');
            } else {
                console.error('Error uploading the photo');
            }
        };
        xhr.send('photo=' + encodeURIComponent(base64Image));
    });
</script>
 
</body>
</html>

PHP 服务器端代码 (upload.php):




<?php
if (isset($_POST['photo'])) {
    $base64Image = $_POST['photo'];
    $image = base64_decode(explode(',', $base64Image)[1]);
    $filename = 'photo.png';
 
    if (file_put_contents($filename, $image)) {
        // 文件保存成功
        echo "Success";
    } else {
        // 文件保存失败
        echo "Failed";
    }
} else {
    // 没有接收到图片数据
    echo "No photo data received";
}
?>

确保你的服务器配置允许通过POST方法上传文件，并且\`u

创建一个能够获取摄像头并拍照上传到PHP服务器的HTML页面

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