ajax formData 上传文件，Servlet 获取文件和参数的方式

在Ajax中使用FormData对象上传文件时，可以在Servlet中通过HttpServletRequest对象获取文件和参数。以下是一个简单的示例：

JavaScript (Ajax) 端:

// 假设你有一个文件输入和其他表单数据
var fileInput = document.getElementById('fileInput');
var formData = new FormData();
formData.append('file', fileInput.files[0]);
formData.append('paramName', 'paramValue'); // 其他表单数据
 
// 使用Ajax发送数据
var xhr = new XMLHttpRequest();
xhr.open('POST', 'uploadServletURL', true);
xhr.onload = function() {
  if (this.status == 200) {
    console.log('File and parameters uploaded successfully');
  }
};
xhr.send(formData);

Java (Servlet) 端:

import java.io.File;
import java.io.IOException;
import java.util.List;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
import org.apache.commons.fileupload.FileItemIterator;
import org.apache.commons.fileupload.FileItemStream;
import org.apache.commons.fileupload.FileItem;
 
@WebServlet("/uploadServlet")
public class UploadServlet extends HttpServlet {
  protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    if (ServletFileUpload.isMultipartContent(request)) {
      try {
        List<FileItem> multiparts = new ServletFileUpload(new DiskFileItemFactory()).parseRequest(request);
        for (FileItem item : multiparts) {
          if (!item.isFormField()) {
            // 处理文件
            String fileName = item.getName();
            // 保存文件到服务器...
            item.write(new File("/path/to/upload/directory" + fileName));
          } else {
            // 处理普通表单字段
            String fieldName = item.getFieldName();
            String fieldValue = item.getString();
            // 根据字段名处理参数...
          }
        }
        response.getWriter().print("File and parameters uploaded successfully");
      } catch (Exception e) {
        e.printS