C语言实现简单的扫雷小程序

以下是一个简单的扫雷游戏的C语言实现示例。程序中包含了布置雷区和处理玩家点击的基本逻辑。

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
 
#define ROWS 3
#define COLS 3
#define MINE_COUNT 1
 
char minefield[ROWS][COLS];
char revealed[ROWS][COLS];
 
void setup() {
    int i, j;
    for (i = 0; i < ROWS; i++) {
        for (j = 0; j < COLS; j++) {
            minefield[i][j] = '*';
            revealed[i][j] = '?';
        }
    }
 
    srand(time(0));
    int mineCount = MINE_COUNT;
    while (mineCount > 0) {
        int row = rand() % ROWS;
        int col = rand() % COLS;
        if (minefield[row][col] == '*') {
            minefield[row][col] = '0' + mineCount;
            mineCount--;
        }
    }
}
 
void printField(char field[ROWS][COLS]) {
    int i, j;
    for (i = 0; i < ROWS; i++) {
        for (j = 0; j < COLS; j++) {
            printf("%c ", field[i][j]);
        }
        printf("\n");
    }
}
 
void reveal(int row, int col) {
    if (revealed[row][col] != '?') {
        printf("This space has already been revealed.\n");
        return;
    }
 
    if (minefield[row][col] == '*') {
        printf("You hit a mine! Game over.\n");
        printField(minefield);
        exit(1);
    } else {
        revealed[row][col] = minefield[row][col];
        printf("You revealed a safe space.\n");
    }
}
 
int main() {
    printf("Welcome to Simple Mine Sweeper!\n");
    setup();
 
    printf("Minefield:\n");
    printField(minefield);
 
    printf("Enter row and column to reveal (e.g., 0 0): ");
    int row, col;
    while (scanf("%d %d", &row, &col) == 2 && row >= 0 && row < ROWS && col >= 0 && col < COLS) {
        reveal(row, col);
        printf("Revealed field:\n");
        printField(revealed);
        printf("Enter row and column to reveal (e.g., 0 0): ");
    }
 
    printf("You won!\n");
    printField(revealed);
 
    return 0;
}

这段代码定义了一个3x3的井字形雷区和一个雷的数量。程序首先设置布置好雷的雷区，然后允许玩家通过输入坐标来点击并显示该位置。如果玩家点击的是雷，游戏结束。如果玩家成功显示了所有安全空间，游戏获胜。这个简单的实现没有包括计算周围雷的数量的功能，这是扫雷游戏的一个常见特性。