华为OD机试 - 灰度图存储（Java & JS & Python & C & C++）

题目描述：

给定一个代表图像的二维整数数组，其中的整数代表颜色值，要求设计一个算法，将该图像转换为灰度图像。

解法1：Java版本

public class Solution {
    public int[][] toGrayImage(int[][] image) {
        int rows = image.length, cols = image[0].length;
        int[][] grayImage = new int[rows][cols];
        for (int i = 0; i < rows; i++) {
            for (int j = 0; j < cols; j++) {
                int originalColor = image[i][j];
                // 转换为灰度值的公式为: gray = 0.3*R + 0.59*G + 0.11*B
                int gray = (int) (0.3 * ((originalColor >> 16) & 0xff) + 
                                  0.59 * ((originalColor >> 8) & 0xff) + 
                                  0.11 * (originalColor & 0xff));
                grayImage[i][j] = (originalColor & 0xff000000) | (gray << 16) | (gray << 8) | gray;
            }
        }
        return grayImage;
    }
}

解法2：JavaScript版本

function toGrayImage(image) {
    let grayImage = image.map(row => {
        return row.map(color => {
            let r = (color >> 16) & 255;
            let g = (color >> 8) & 255;
            let b = color & 255;
            let gray = Math.floor(0.3 * r + 0.59 * g + 0.11 * b);
            return (color & 0xff000000) | (gray << 16) | (gray << 8) | gray;
        });
    });
    return grayImage;
}

解法3：Python版本

def to_gray_image(image):
    gray_image = [[int(((color >> 16) & 0xff) * 0.3 +
                       ((color >> 8) & 0xff) * 0.59 +
                       (color & 0xff) * 0.11) for color in row] for row in image]
    return [[(color << 16) | (color << 8) | color | (color >> 24) << 24 for color in row] for row in gray_image]

解法4：C语言版本

#include <stdint.h>
 
void toGrayImage(int **image, int rows, int *cols, int ***grayImage) {
    *grayImage = (int **) malloc(sizeof(int *) * rows);
    for (int i = 0; i < rows; i++) {
        (*grayImage)[i] = (int *) malloc(sizeof(int) * (*cols));
        for (int j = 0; j < *cols; j++) {
            int originalColor = image[i][j];
            int gray = (int) (0.3 * (((originalColor >> 16) & 0xff