以下是一个简化的Java代码示例，用于模拟操作系统中的理发店问题。这个例子中，我们假设有一个理发店有一个理发师和一个等候区，理发师在等候区有客户时开始理发。
import java.util.concurrent.BlockingQueue;
import java.util.concurrent.LinkedBlockingQueue;
public class BarbershopProblem {
public static void main(String[] args) {
BlockingQueue<Customer> waitingRoom = new LinkedBlockingQueue<>();
Thread barberThread = new Thread(new Barber(waitingRoom));
barberThread.start();
for (int i = 0; i < 10; i++) {
Customer customer = new Customer(i, waitingRoom);
Thread customerThread = new Thread(customer);
customerThread.start();
}
}
}
class Barber implements Runnable {
private final BlockingQueue<Customer> waitingRoom;
public Barber(BlockingQueue<Customer> waitingRoom) {
this.waitingRoom = waitingRoom;
}
@Override
public void run() {
try {
while (true) {
Customer customer = waitingRoom.take();
System.out.println("理发师开始为客户 " + customer.id + " 理发");
// 模拟理发过程
Thread.sleep(1000 + (long) (Math.random() * 1000));
System.out.println("客户 " + customer.id + " 理发完毕");
}
} catch (InterruptedException e) {
Thread.currentThread().interrupt();
}
}
}
class Customer implements Runnable {
public final int id;
private final BlockingQueue<Customer> waitingRoom;
public Customer(int id, BlockingQueue<Customer> waitingRoom) {
this.id = id;
this.waitingRoom = waitingRoom;
}
@Override
public void run() {
try {
System.out.println("客户 " + id + " 等待理发");
waitingRoom.put(this);
} catch (InterruptedException e) {
Thread.currentThread().interrupt();
}
}
}这段代码模拟了理发店问题。理发师（Barber）是一个无限循环，不断从等候区（waitingRoom）中取出客户（Customer）进行理发。每个客户（Customer）是一个线程，它们在等候区等待被理发师服务。这个简化的例子使用了BlockingQueue来实现等候区，并且使用线程来模拟并发。